Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 97

Answer

$1\frac{5}{27}$

Work Step by Step

$-3\frac{1}{5}\div(-2\frac{7}{10})$ $=3\frac{1}{5}\div2\frac{7}{10}$ $=\frac{16}{5}\div\frac{27}{10}$ $=\frac{16}{5}\times\frac{10}{27}$ $=\frac{16}{1}\times\frac{2}{27}$ $=\frac{32}{27}$ $=1\frac{5}{27}$
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