Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 110

Answer

$-\frac{7}{12x}$

Work Step by Step

$\frac{7}{8x}\times-\frac{2}{3}$ $=-(\frac{7}{8x}\times\frac{2}{3})$ $=-(\frac{7}{4x}\times\frac{1}{3})$ $=-\frac{7}{12x}$
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