Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 66

Answer

$\frac{4+3b}{15}$

Work Step by Step

$\frac{4}{15}+\frac{b}{5}=\frac{4}{15}+\frac{b\times3}{5\times3}=\frac{4}{15}+\frac{3b}{15}=\frac{4+3b}{15}$
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