Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 63

Answer

$-\frac{1}{12}$

Work Step by Step

$-\frac{1}{3}+\frac{1}{4}=-\frac{1\times4}{3\times4}+\frac{1\times3}{4\times3}=-\frac{4}{12}+\frac{3}{12}=-\frac{1}{12}$
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