Answer
The cost of the games is \$110.
The cost of the system is \$330.
Work Step by Step
Let the cost of the games be g.
The cost of the system is 3g.
$g+3g=440$
$4g=440$
$4g\div4=440\div4$
$g=110$
$3g=3\times110=330$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 3 - Section 3.4 - Linear Equations in One Variable and Problem Solving - Exercise Set - Page 197: 33
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