Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Test - Page 159: 21

Answer

$-5$

Work Step by Step

$\frac{|25-30|^2}{2(-6)+7}$ $\longrightarrow$resolve absolute value $\frac{5^2}{2(-6)+7}$ $\longrightarrow$resolve exponent $\frac{25}{2(-6)+7}$ $\longrightarrow$multiply $\frac{25}{(-12)+7}$ $\longrightarrow$simplify denominator $\frac{25}{-5}$ $\longrightarrow$divide $-5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.