Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Test: 21

Answer

$-5$

Work Step by Step

$\frac{|25-30|^2}{2(-6)+7}$ $\longrightarrow$resolve absolute value $\frac{5^2}{2(-6)+7}$ $\longrightarrow$resolve exponent $\frac{25}{2(-6)+7}$ $\longrightarrow$multiply $\frac{25}{(-12)+7}$ $\longrightarrow$simplify denominator $\frac{25}{-5}$ $\longrightarrow$divide $-5$
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