Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Test: 19

Answer

-2

Work Step by Step

$\frac{4}{2}-\frac{8^2}{16}$ $\longrightarrow$resolve exponent =$\frac{4}{2}-\frac{64}{16}$ $\longrightarrow$convert to like fraction =$\frac{4\times8}{2\times8}-\frac{64}{16}$ $\longrightarrow$multiply =$\frac{32}{16}-\frac{64}{16}$ $\longrightarrow$subtract numerators =$\frac{-32}{16}$ $\longrightarrow$divide =$-2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.