Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Section 2.5 - Order of Operations - Exercise Set: 108

Answer

-1932

Work Step by Step

To evaluate, substitute the given values. $3x^2+2x-y$ =$3(-18)^2+2(-18)-2868$ =$3(-18)^2+2(-18)-2868$ =$3(324)-36-2868$ =$972-36-2868$ =$-1932$
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