Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Section 2.5 - Order of Operations - Exercise Set: 58

Answer

-4

Work Step by Step

$\frac{10(-1)-(-2)(-3)}{2[-8\div(-2-2)]}=\frac{-10-6}{2[-8\div(-4)]}=\frac{-16}{2[2]}=\frac{-16}{4}=-4$
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