Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Section 2.5 - Order of Operations - Exercise Set: 57

Answer

-3

Work Step by Step

$\frac{(-7)(-3)-(4)(3)}{3[7\div(3-10)]}=\frac{21-12}{3[7\div(-7)]}=\frac{9}{3[-1]}=\frac{9}{-3}=-3$
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