Answer
2
Work Step by Step
$(3-7)^2\div(6-4)^3$ $\longrightarrow$resolve expressions in parenthesis
$(-4)^2\div(2)^3$ $\longrightarrow$resolve exponents
$16\div8$ $\longrightarrow$divide
$2$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 2 - Review - Page 157: 125
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