Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Test - Page 729: 11

Answer

$72a^{20}b^5$

Work Step by Step

$(3a^4b)^2(2ba^4)^3\rightarrow$ simplify using power property of exponents =$(9a^8b^2)(8b^3a^{12})\rightarrow$ simplify using product property of exponents =$72a^{20}b^5$
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