Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.3 - Multiplying Polynomials - Exercise Set: 13

Answer

$a^3-33a+18$

Work Step by Step

$(a+6)(a^2-6a+3)=a(a^2)+a(-6a)+a(3)+6(a^2)+6(-6a)+6(3)=a^3-6a^2+3a+6a^2-36a+18=a^3-33a+18$
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