Answer
$12a^4b^5\ m^2$
Work Step by Step
The area of a triangle is $\frac{1}{2}bh$.
$\frac{1}{2}(6a^3b^4)(4ab)=(\frac{1}{2})(6)(4)(a^{(3+1)})(b^{(4+1)})=12a^4b^5$
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