Answer
$35b^{19}$
Work Step by Step
$b\times7b^{10}\times5b^8=(1\times7\times5)(b\times b^{10}\times b^8)=35(b^{1+10+8})=35b^{19}$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 10 - Section 10.2 - Multiplication Properties of Exponents - Exercise Set - Page 710: 12
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