Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Section 1.8 - Introduction to Variables, Algebraic Expressions, and Equations - Exercise Set: 43

Answer

1: 16 ft 2: 64 ft 3: 144 ft 4: 256 ft

Work Step by Step

Substitute each value for t and solve. $16\times1^2=16\times1=16$ $16\times2^2=16\times4=64$ $16\times3^2=16\times9=144$ $16\times4^2=16\times16=256$
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