Answer
$3$
Work Step by Step
Solve using PEMDAS (The priority list for solving expressions: Parentheses, exponents, [multiplication, division], [addition, subtraction]. For the operations in the brackets, solve from left to right)
$\dfrac{2+4^2}{5(20-16)-3^2-5} = \dfrac{2+4^2}{5\cdot 4-3^2-5} = \dfrac{2+16}{5\cdot 4-9-5} = \dfrac{2+16}{20-9-5} = \dfrac{18}{6} = 3$