Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Section 1.7 - Exponents and Order of Operations - Exercise Set: 62

Answer

$3$

Work Step by Step

Solve using PEMDAS (The priority list for solving expressions: Parentheses, exponents, [multiplication, division], [addition, subtraction]. For the operations in the brackets, solve from left to right) $\dfrac{40+8}{5^2-3^2} = \dfrac{40+8}{25-9} = \dfrac{48}{16} = 3$
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