Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Practice: 3

Answer

12$a^{3}b^{10}$

Work Step by Step

Subtract the exponents: $a^{4}-a$ (aka, a^1)= $a^{3}$ $b^{11}-b$ (aka, b^1)=$b^{10}$ Keep the 12. So you end up with 12$a^{3}b^{10}$
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