Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5: 13

Answer

(x-3)(x-5)

Work Step by Step

$x^{2}$ - 8x + 15 step 1. Enter x as the first term of each factor $x^{2}$ - 8x + 15 = (x__)(x _) Step 2. To find the second term of each factor, we must find two integers whose product is 15 and whose sum is -8 List pairs of factors of the constant, 15 (1,15)(-1,-15)(-3,-5)(3,5) step 3. The correct factorization of $x^{2}$ - 8x + 15 is the one in which the sum of the Outside and Inside products is equal to -8x. So (-3,-5) satisfy the condition $x^{2}$ -8x + 15 = $x^{2}$ -3x -5x + 15 = (x-3)(x-5)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.