Answer
\[x\ge \frac{7+48y}{6}\].
Work Step by Step
Given is an inequality \[Ax+By\le C;A<0\], where \[A,B,C\] are constants.
An equivalent inequality can be found by substituting any values for \[A,B,C\], which also fulfills the condition \[A<0\].
Use the property of inequality, which says that an inequality changes the sign if divided by a negative quantity. An equivalent inequality can be written as follows:
\[-6x+48y\le -7\]
This inequality is restructured with \[x\] isolated on left side as:
\[\begin{align}
& x\ge \frac{-7-48y}{-6} \\
& x\ge \frac{7+48y}{6} \\
\end{align}\]
The equivalent inequality is given as \[x\ge \frac{7+48y}{6}\].
