Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 363: 91

Answer

the solution set is \[\left\{ 0 \right\}\].

Work Step by Step

The equation is \[\frac{x}{2}-\frac{x}{4}+4=x+4\]. Subtract \[4\]from both sides of the equal sign. \[\begin{align} & \frac{x}{2}-\frac{x}{4}+4-4=x+4-4 \\ & \frac{x}{2}-\frac{x}{4}=x \\ & \frac{2x}{4}-\frac{x}{4}=x \\ & \frac{x}{4}=x \\ \end{align}\] Multiply by 4 both sides of the equal sign. \[x=4x\] Subtract \[x\]from both sides of the equal sign. \[\begin{align} & x-x=4x-x \\ & 0=3x \\ & 0=x \\ \end{align}\] Check the proposed solution. Substitute 0 for x in the original equation \[\frac{x}{2}-\frac{x}{4}+4=x+4\] \[\begin{align} & \frac{0}{2}-\frac{0}{4}+4=0+4 \\ & 4=4 \\ \end{align}\] This true statement \[4=4\] verifies that the solution set is \[\left\{ 0 \right\}\]. Thus, the solution set is \[\left\{ 0 \right\}\].
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