Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 336: 104

Answer

$3^5 \cdot 3^{-2} = 3^3 = 27$

Work Step by Step

RECALL: For any non-zero real number $a$, $a^m \cdot a^n = a^{m+n}$ Use the rule above to find: $=3^{5+(-2)} \\=3^3 \\=27$
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