Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises: 70

Answer

$3$

Work Step by Step

RECALL: For positive real numbers $a$ and $b$, $\dfrac{\sqrt{a}}{\sqrt{b}} = \sqrt{\dfrac{a}{b}}$ Use the rule above to obtain: $=\sqrt{\dfrac{27}{3}} \\=\sqrt{9} \\=\sqrt{3^2} \\=3$
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