Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises: 69

Answer

$2\sqrt{3}$

Work Step by Step

RECALL: For positive real numbers $a$ and $b$, $\dfrac{\sqrt{a}}{\sqrt{b}} = \sqrt{\dfrac{a}{b}}$ Use the rule above to obtain: $=\sqrt{\dfrac{24}{2}} \\=\sqrt{12}$ Factor the radicand so that one of the factors is a perfect square to obtain: $=\sqrt{4(3)} \\=\sqrt{2^2(3)}$ Bring out the square root of the perfect square factor to obtain: $=2\sqrt{3}$
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