Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises: 51

Answer

$-\dfrac{1}{4}$

Work Step by Step

Convert each mixed numebr to improper fraction to find: $=-\dfrac{3(1)+2}{3} \div \dfrac{3(6)+2}{3} \\=-\dfrac{5}{3} \div \dfrac{20}{3}$ Use the rule $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \cdot \frac{d}{c}$ to find: $=-\dfrac{5}{3} \cdot \dfrac{3}{20}$ Cancel the common factors, 3 and 5, to find: $=-\frac{1}{1} \cdot \frac{1}{4}$ Multiply the numerators together and the denominators together to find: $=-\dfrac{1(1)}{1(4)} \\=-\dfrac{1}{4}$
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