Answer
$\dfrac{1}{4}$
Work Step by Step
(i) $a^m \cdot a^n = a^{m+n}$
(ii) $\dfrac{a^m}{a^n}=a^{m-n}, a \ne 0$
Use rule (i) to find:
$=2^{-3+1}
\\=2^{-2}$
Use rule (ii) to find:
$=\dfrac{1}{2^2}
\\=\dfrac{1}{4}$
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 5 - Number Theory and the Real Number System - 5.6 Exponents and Scientific Notation - Exercise Set 5.6 - Page 320: 28
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