Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.6 Exponents and Scientific Notation - Exercise Set 5.6: 28

Answer

$\dfrac{1}{4}$

Work Step by Step

(i) $a^m \cdot a^n = a^{m+n}$ (ii) $\dfrac{a^m}{a^n}=a^{m-n}, a \ne 0$ Use rule (i) to find: $=2^{-3+1} \\=2^{-2}$ Use rule (ii) to find: $=\dfrac{1}{2^2} \\=\dfrac{1}{4}$
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