Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.5 Real Numbers and Their Properties; Clock Addition - Exercise Set 5.5 - Page 310: 86

Answer

No, it does not. The positions (or order) of the factors were changed, so the statement illustrates the commutative property of multiplication.

Work Step by Step

The commutative property of multiplication states that for any real numbers $a, b, $ and $c$: $a \cdot (b \cdot c)= a \cdot (c \cdot b)$ The associative property of multiplication states that for any real numbers $a, b, $ and $c$: $a \cdot (b \cdot c)= (a \cdot b) \cdot c$ Thus, the given statement illustrates the commutative property as the positions of $c$ and $b$ were switched.
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