Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.3 The Rational Numbers - Exercise Set 5.3 - Page 285: 111

Answer

Two rational numbers of the form \[\frac{a}{b}\]and \[\frac{c}{d}\] can be multiplied by dividing the product of numerators from the product of denominators. This can be shown as follows: \[\frac{a}{b}\times \frac{c}{d}=\frac{a\cdot c}{b\cdot d}\] The product of the two rational numbers thus gives: \[\begin{align} & \frac{13}{4}\times \frac{13}{9}=\frac{13\times 13}{4\times 9} \\ & =\frac{169}{36} \end{align}\] Two rational numbers\[\frac{a}{b}\]and \[\frac{c}{d}\] can be added by first finding the least common multiple of their denominators also known as least common denominator. The rational numbers are then multiplied by a rational number of the form \[\frac{e}{e}\] so that the denominator of both the rational numbers becomes the least common denominators as found earlier. The least common denominator of the rational numbers \[\frac{13}{4},\frac{13}{9}\]is \[36\]. Thus, the addition oftwo rational numbers can be shown as: \[\begin{align} & \frac{13}{4}+\frac{13}{9}=\frac{13}{4}\times \frac{9}{9}+\frac{13}{9}\times \frac{4}{4} \\ & =\frac{13\times 9+13\times 4}{36} \\ & =\frac{169}{36} \end{align}\] We conclude that \[\frac{13}{4}+\frac{13}{9}\] and \[\frac{13}{4}\times \frac{13}{9}\]give the same answer.
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