Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.3 Computation in Positional Systems - Exercise Set 4.3 - Page 235: 44

Answer

The multiplication of two given numbers in base two is \[{{1001110}_{\text{two}}}\].

Work Step by Step

Since the computation involves base two, the only digits which are allowed are 0 and 1. The procedure to multiply two numbers in base two is same as in base ten. \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] Hence, first multiply \[{{0}_{\text{two}}}\] in first column from right, with \[{{1}_{\text{two}}}\] which is above it in the same column: \[{{0}_{\text{two}}}\times {{1}_{\text{two}}}={{0}_{\text{two}}}\]. Now, write \[{{0}_{\text{two}}}\] in the first column from right, below the horizontal line: \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] \[{{0}_{\text{two}}}\] Similarly, multiply \[{{0}_{\text{two}}}\] with the remaining digits of \[{{1101}_{\text{two}}}\]: \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] \[{{0000}_{\text{two}}}\] Repeat whole procedure, but with \[{{1}_{\text{two}}}\]. First, place the symbol \[\times \] below \[{{0}_{\text{two}}}\]in \[{{0000}_{\text{two}}}\]. \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] \[{{0000}_{\text{two}}}\] \[\times \] Now, multiply \[{{1}_{\text{two}}}\] in second column from right, with \[{{1}_{\text{two}}}\] in the first column from right: \[{{1}_{\text{two}}}\times {{1}_{\text{two}}}={{1}_{\text{two}}}\] Write \[{{1}_{\text{two}}}\] below\[{{0}_{\text{two}}}\]in \[{{0000}_{\text{two}}}\]: \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] \[{{0000}_{\text{two}}}\] \[1\times \] Similarly, multiply \[{{1}_{\text{two}}}\] with the remaining digits of \[{{1101}_{\text{two}}}\]: \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] \[{{0000}_{\text{two}}}\] \[1101\times \] Once again multiply \[{{1}_{\text{two}}}\] with \[{{1101}_{\text{two}}}\] in the same manner, after placing two symbols of \[\times \] as shown: \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] \[{{0000}_{\text{two}}}\] \[1101\times \] \[+\underline{1101\times \times }\] Now, add together \[{{0000}_{\text{two}}}\], \[{{1101}_{\text{two}}}\] and \[{{1101}_{\text{two}}}\] in the manner shown above: \[{{1101}_{\text{two}}}\] \[\underline{\times {{110}_{\text{two}}}}\] \[{{0000}_{\text{two}}}\] \[1101\times \] \[+\underline{1101\times \times }\] \[{{1001110}_{\text{two}}}\] Now, to check whether the above obtained solution is correct, perform the multiplication by converting each number to base ten: \[{{1101}_{\text{two}}}=13\], \[{{110}_{\text{two}}}=6\]and \[{{1001110}_{\text{two}}}=78\]. Since, \[13\times 6\] indeed equals 78, the solution obtained is correct. Hence, the multiplication of two given numbers in base two is \[{{1001110}_{\text{two}}}\].
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