Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.1 Our Hindu-Arabic System and Early Positional Systems - Exercise Set 4.1: 66

Answer

$0.6812$

Work Step by Step

RECALL: $10^{-1} = \dfrac{1}{10} = 0.1 \\10^{-2} = \dfrac{1}{10^2} = 0.01 \\10^{-3} = \dfrac{1}{10^3} = 0.001 \\10^{-4} =\dfrac{1}{10^4} = 0.0001 \\10^{-5} = \dfrac{1}{10^5} = 0.00001 \\10^{-6} = \dfrac{1}{10^6} = 0.000001$ Thus, the given expression is equivalent to: $=(6 \times 0.1) + (8 \times 0.01) + (1 \times 0.001) + (2 \times 0.0001) \\=0.6 + 0.08 + 0.001 + 0.0002 \\=0.6812$
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