Answer
$\sim p\rightarrow \sim q$.
Work Step by Step
$p\rightarrow q$'s inverse is $\sim p\rightarrow \sim q$.
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 3 - Logic - 3.5 Equivalent Statements and Variations of Conditional Statements - Concept and Vocabulary Check - Page 169: 4
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