Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.4 Truth Tables for the Conditional and the Biconditional - Exercise Set 3.4 - Page 160: 59

Answer

(a) The given compound statement can be written in simple statements \[p,q,r\] as shown below, \[\begin{align} & p\text{ : You cut and paste from the internet}\text{. } \\ & q\text{: }\ \text{You cite the source}\text{. } \\ & r\text{: }\ \text{You will be charged with plagiarism}\text{.} \\ \end{align}\] Use the representation to re-write the provided statement as, If p and not q, then r. ‘If-then’ is represented by the symbol ‘\[\to \]’, ‘Not or negation’ is represented by the symbol ‘\[\sim \]’, and ‘And’ is represented by the symbol ‘\[\wedge \]’. Use the symbols to determine the symbolic form of the provided statement as, \[\left( p\wedge \sim q \right)\to r\] Hence, the symbolic form for the provided statement is, \[\left( p\wedge \sim q \right)\to r\]. (b) The truth table is as follows: c) The truth table for \[\left( p\wedge \sim q \right)\to r\] is as follows: It can be seen from the truth table that the statement \[\left( p\wedge \sim q \right)\to r\]is false when the statement \[p\wedge \sim q\] is true and the statement \[r\] is false. Hence, the provided statement is false when \[p\wedge \sim q\text{ is true and r is false}\].
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