Answer
(a)
The provided compound statement can be written in simple statements as\[p,q\].
Here, \[p,q\]represents two simple statements:
\[\begin{align}
& p\text{: You do a little bit each day} \\
& q\text{: you will get by}\text{. }
\end{align}\]
Therefore, the provided statement can be written in the symbolic form as:
\[\left( p\to q \right)\wedge \left( \sim p\to \sim q \right)\].
(b)
The truth table is as follows:
(c)
From the truth table, it is clear that when the expression in parenthesis assumes true value, then the final statement has true as result. Then, it is false in all other cases.
So, from the truth table it can be stated that when the truth value of the\[\left( p\to \sim q \right),\left( \sim p\to q \right)\], are having different truth values, the given compound statement \[\left( p\to \sim q \right)\wedge \left( \sim p\to q \right)\]assumes false value.
Therefore, it is false when the value of the \[\left( p\to \sim q \right),\left( \sim p\to q \right)\] are different truth values.
