Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 13 - Voting and Apportionment - 13.3 Apportionment Method - Exercise Set 13.3 - Page 875: 18

Answer

Using Webster's method, the officers are apportioned to the precincts as follows: Precinct A is apportioned 28 officers. Precinct B is apportioned 34 officers. Precinct C is apportioned 53 officers. Precinct D is apportioned 14 officers. Precinct E is apportioned 22 officers. Precinct F is apportioned 29 officers.

Work Step by Step

We can find the total number of crimes. total crimes = 446 + 526 + 835 + 227 + 338 + 456 total crimes = 2828 We can find the standard divisor. $standard ~divisor = \frac{total ~crimes}{officers}$ $standard ~divisor = \frac{2828}{180}$ $standard ~divisor = 15.71$ If we use the standard divisor and round each standard quota to the nearest whole number, the sum of the apportioned officers will be 179 officers. To obtain a sum of 180 officers, we need to find a modified divisor that is slightly less than the standard divisor. Let's choose a modified divisor of 15.7. Note that it may take some trial-and-error to find a modified divisor that works. We can find the modified quota for each precinct. Precinct A: $modified~quota = \frac{crimes}{modified~divisor}$ $modified~quota = \frac{446}{15.7}$ $modified~quota = 28.41$ Precinct B: $modified~quota = \frac{crimes}{modified~divisor}$ $modified~quota = \frac{526}{15.7}$ $modified~quota = 33.503$ Precinct C: $modified~quota = \frac{crimes}{modified~divisor}$ $modified~quota = \frac{835}{15.7}$ $modified~quota = 53.18$ Precinct D: $modified~quota = \frac{crimes}{modified~divisor}$ $modified~quota = \frac{227}{15.7}$ $modified~quota = 14.46$ Precinct E: $modified~quota = \frac{crimes}{modified~divisor}$ $modified~quota = \frac{338}{15.7}$ $modified~quota = 21.53$ Precinct F: $modified~quota = \frac{crimes}{modified~divisor}$ $modified~quota = \frac{456}{15.7}$ $modified~quota = 29.04$ Using Webster's method, we apportion the officers by rounding the modified quota to the nearest whole number. The officers are apportioned to the precincts as follows: Precinct A is apportioned 28 officers. Precinct B is apportioned 34 officers. Precinct C is apportioned 53 officers. Precinct D is apportioned 14 officers. Precinct E is apportioned 22 officers. Precinct F is apportioned 29 officers. Note that the sum of the apportioned officers is 180, so using a modified divisor of 15.7 is acceptable.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.