Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - Chapter Summary, Review, and Test - Review Exercises - Page 760: 83

Answer

$\frac{1}{36}$

Work Step by Step

We know that $probability=\frac{\text{number of favorable outcomes}}{\text{number of all outcomes}}$ The events are independent, so we can find the probability of all of them happening by finding the probability of them happening individually and multiplying those. The probability of the yellow: $\frac{2}{6}=\frac{1}{3}$, the probability of the $4$: $\frac{1}{6}$, the probability of the odd number: $\frac{3}{6}=\frac{1}{2}$, thus the probability of all of them happening is: $\frac{1}{3}\frac{1}{6}\frac{1}{2}=\frac{1}{36}$
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