Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6: 45

Answer

$\frac{113}{174}$

Work Step by Step

If A and B are not mutually exclusive events, then P(A or B) = P(A)+P(B) - P(A and B) E: has completed four years of high school only or is a man. A: has completed four years of high school only B: a man P(A) = $\frac{56}{174}$ P(B) = $\frac{82}{174}$ P(A and B) = $\frac{25}{174}$ P(E) = $\frac{56}{174}$ + $\frac{82}{174}$ - $\frac{25}{174}$ =$\frac{56 + 82 - 25}{174}$ = $\frac{113}{174}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.