Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.4 Fundamentals of Probability - Exercise Set 11.4 - Page 716: 54

Answer

The probability of a child, who is healthy is\[\frac{1}{4}\].

Work Step by Step

The sample space is\[S=\left\{ SS,Ss,sS,ss \right\}\]. Thus, the number of possible outcomes are 4.The probability of an even E can be calculated by dividing the number of outcomes in an event E by the total number of the possible outcomes. Compute the probability of a child, who is healthy using the equation as shown below: \[\begin{align} & P\left( E \right)=\frac{\text{number of outcomes in event }E}{\text{total number of possible outcomes}} \\ & P\left( \text{healthy} \right)=\frac{1}{4} \end{align}\] Hence, the probability of a child, who is healthy is\[\frac{1}{4}\].
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