Answer
The probability of a child having sickle cell trait is\[\frac{1}{2}\].
Work Step by Step
The sample space\[S=\left\{ SS,Ss,sS,ss \right\}\]. Thus, number of possible outcomes are 4.The probability of an even E can be calculated by dividing the number of outcomes in an event E by the total number of the possible outcomes.
Compute the probability of a child having sickle cell trait using the equation as shown below:
\[\begin{align}
& P\left( E \right)=\frac{\text{number of outcomes in event }E}{\text{total number of possible outcomes}} \\
& P\left( \text{having sickle cell trait} \right)=\frac{2}{4} \\
& =\frac{1}{2}
\end{align}\]
