Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.4 Fundamentals of Probability - Exercise Set 11.4 - Page 716: 51

Answer

$\frac{1}{4}$

Work Step by Step

P(E) = $\frac{no. of outcomes in favor}{Total no of outcomes}$ A person with two sickle cell genes will have the disease, but a person with only one sickle cell gene will have a mild, nonfatal anemia called sickle cell trait. E: Is healthy Favorable outcomes= {SS} P(E) = $\frac{1}{4}$
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