Answer
1
Work Step by Step
P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$
A single die is rolled twice. The 36 equally likely outcomes are shown in the attached picture.
E: two numbers whose sum is less than 13.
Since the greatest number is 6, if we add 6 from both the outcomes, we find that the maximum value is 12. Therefore, all outcomes are favorable.
Favorable outcomes= {all}
P(E) = $\frac{36}{36}$ =1
