Answer
$\frac{1}{9}$
Work Step by Step
P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$
A single die is rolled twice. The 36 equally likely outcomes are shown in the attached picture.
E: two numbers whose sum is 5.
Favorable outcomes= {(1,4),(2,3),(3,2),(4,1)}
P(E) = $\frac{4}{36}$ = $\frac{1}{9}$
