Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.2 Permutations - Exercise Set 11.2: 7

Answer

362880

Work Step by Step

The number of possible permutations if r objects are taken from n itself is nPr = $\frac{n!}{(n-r)!}$ The number of different ways you can arrange the books, assuming that the order of the books makes a difference to you, is: 9P9 = $\frac{9!}{(9-9)!}$ = 362880 ways
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