Answer
714
Work Step by Step
See Factorial Notation, page 696:
$n!=n(n-1)(n-2)\cdots(3)(2)(1)$
and, by definition, $0!=1$
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$6!=6\times 5\times 4\times 3\times 2\times 1=720$
$3!=3\times 2\times 1=6$
$6!-3!=714$
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