Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.6 Right Triangle Trigonometry - Exercise Set 10.6 - Page 665: 7

Answer

Value of \[\sin A=\frac{4}{5}\], \[\cos A=\frac{3}{5}\], and \[\tan A=\frac{4}{3}\].

Work Step by Step

The length of hypotenuse that is \[\left( c=35 \right)\], Side adjacent to acute angle A that is \[\left( b=21 \right)\]. First, compute side opposite to acute angle A that is a, using the Pythagorean Theorem. Compute the side opposite to acute angle A that is a; of a triangle, by the below mentioned formula: \[\begin{align} & c\text{ }=\sqrt{{{a}^{2}}+{{b}^{2}}} \\ & \text{35 }=\sqrt{{{a}^{2}}+{{21}^{2}}} \\ & {{35}^{2}}={{a}^{2}}+{{21}^{2}} \\ & 1225={{a}^{2}}+441 \end{align}\] Further it can be simplified as: \[\begin{align} & {{a}^{2}}=1225-441 \\ & {{a}^{2}}=784 \end{align}\] Take square root both the sides as follows: \[\begin{align} & \sqrt{{{a}^{2}}}=\sqrt{784} \\ & a=28 \end{align}\] Now, compute the different trigonometric ratios using the formulas: \[\begin{align} & \sin \text{ }A=\frac{\text{Side opposite to angle }A}{\text{Hypotenuse}} \\ & =\frac{28}{35} \\ & =\frac{4}{5} \end{align}\] Therefore, \[\sin A=\frac{4}{5}\] \[\begin{align} & \cos \text{ }A=\frac{\text{Side adjacent to angle }A}{\text{Hypotenuse}} \\ & =\frac{21}{35} \\ & =\frac{3}{5} \end{align}\] Therefore, \[\cos A=\frac{3}{5}\] \[\begin{align} & \text{tan }A=\frac{\text{Side opposite angle }A}{\text{Side adjacent to angle }A} \\ & =\frac{28}{21} \\ & =\frac{4}{3} \end{align}\] Therefore, \[\tan A=\frac{4}{3}\] Hence, the value of trigonometric ratios is, \[\sin A=\frac{4}{5}\], \[\cos A=\frac{3}{5}\], and \[\tan A=\frac{4}{3}\].
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.