Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.3 Polygons, Perimeter, and Tessellations - Exercise Set 10.3 - Page 637: 39

Answer

Dimensions are\[200\text{ yd}\]and \[50\text{ yd}\], respectively.

Work Step by Step

The length and width of a rectangular field will be determined by finding the perimeter of the field in the yard. Computation of length, l and width w of the field by the perimeter can be done by using the formula\[P=2l+2w\]. Length, l is 4 times of the width, w. Compute the length and width as shown below: \[\begin{align} & P=2l+2w \\ & =2\left( l+w \right) \end{align}\] Substitute the values in the equation above as follows: \[\begin{align} & 500\text{ yd}=2\left( 4w+w \right) \\ & 500\text{ yd}=10w \\ & w=\frac{50\text{yd}}{1} \\ & =50\text{ yd} \end{align}\] Compute the value of l as mentioned below: \[\begin{align} & l=4\times w \\ & =4\times 50\text{ yd} \\ & =200\text{ yd} \end{align}\] Hence, the length and width of a rectangular field are \[200\text{ yd}\]and\[50\text{ yd}\], respectively.
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