Answer
\[\Delta \text{I}\cong \Delta \text{II}\]by ASA condition.
Work Step by Step
The figure shows that the triangle I and the triangle II contains equal sides marked with one tick and side AB is parallel to side CD.
The angles that are opposite to the side marked with one tick in triangle I and triangle II form a pair of vertically opposite angles with equal measurement.
Since AB is parallel to CD, angle A in triangle I and angle D in triangle II form a pair of alternate interior angles with equal measurement. Hence, \[\angle A=\angle D\].
The measurement of two angles of triangle I are equal to the measurement of the two angles of triangle II and the length of the sides are also equal in triangle I and triangle II, hence the two triangles are congruent by ASA condition.
