## Thinking Mathematically (6th Edition)

($\frac{-4}{7}$,$\frac{16}{49}$)
($\frac{2}{3}$,$\frac{4}{9}$),($\frac{1}{5}$,$\frac{1}{25}$),(7,49),($\frac{-5}{6}$,$\frac{25}{36}$),($\frac{-4}{7}$,_) In every interval the second number is square of the first number So in the last interval the second number is $\frac{16}{49}$ ($\frac{-4}{7}$,$\frac{16}{49}$)