Answer
$P(8,3) = {8 \choose 3} *3!$
Work Step by Step
The number of ways to permute 3 elements is the same as the number of ways to choose the elements and then order them. Therefore, we can say that $P(8,3)$ is $8 \choose 3$ multiplied by the number of ways to order the 3 elements, or $3! = 6$.