Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 9 - Counting and Probability - Exercise Set 9.5 - Page 581: 3

Answer

$P(7,2) = {7 \choose 2}*2!$

Work Step by Step

The number of ways to permute 2 elements is the same as the number of ways to choose the elements and then order them. Therefore, we can say that $P(7,2)$ is $7 \choose 2$ multiplied by the number of ways to order the 2 elements, or $2! = 2$.
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